WebJul 31, 2012 · if you have index on column date_fin then to get the best performance you can use: WHERE l.date_fin BETWEEN CAST (DATE_SUB (CURRENT_DATE, INTERVAL 6 MONTH) AS DATETIME) AND DATE_SUB (CAST (DATE_SUB (CURRENT_DATE, INTERVAL 1 DAY) AS DATETIME), INTERVAL 1 MINUTE); Share Improve this answer … WebAug 19, 2024 · MySQL DATE_SUB () function subtract a time value (as interval) from a date. Syntax: DATE_SUB (date, INTERVAL expr unit) Arguments: Video Presentation: Your browser does not support HTML5 video. Pictorial Presentation: Example: MySQL DATE_SUB () function
MySQL DATE_SUB() Complete Guide to MySQL DATE_SUB()
WebMay 12, 2014 · So far I've tried. DATE_SUB (NOW (), INTERVAL 1 MONTH) Here is the context: SELECT contracts.currency , ROUND (SUM ( CASE WHEN contracts.currency … WebSep 21, 2011 · SELECT * FROM table1 WHERE MONTH (mydate) BETWEEN MONTH (DATE_SUB (now (), INTERVAL 3 MONTH)) AND MONTH (now ()) AND YEAR (mydate) BETWEEN YEAR (DATE_SUB (now (), INTERVAL 3 MONTH)) AND YEAR (now ()) This latter version will run much slower, because it cannot use an index for mydate however. … how many minutes to boil 1 egg
MySQL query to group by age, 3 months, 6 months, 9 months and 12 months
WebJan 24, 2014 · SELECT DISTINCT user_id, COUNT (post_id) as pc FROM diaries_posts WHERE post_date < DATE_SUB ( NOW ( ) , INTERVAL -6 MONTH ) GROUP BY user_id Out of which I'm pretty sure the average part (2nd part) is wrong, since I'm not getting AVG_NO_OF_POST per DISTINCT_USER but TOTAL_NO_OF_POSTS per … WebFeb 9, 2024 · Date/Time Functions Function Description Example (s) age ( timestamp, timestamp ) → interval Subtract arguments, producing a “symbolic” result that uses years and months, rather than just days age (timestamp '2001-04-10', timestamp '1957-06-13') → 43 years 9 mons 27 days age ( timestamp ) → interval Subtract argument from … WebNov 12, 2024 · select (case when date >= date_sub (now (), interval 3 month) then '3month' when date >= date_sub (now (), interval 6 month) then '6month' when date >= date_sub (now (), interval 9 month) then '9month' when date >= date_sub (now (), interval 12 month) then '12month' end) as grp, sum (cost) as sumcost from table t … how many minutes till dark