WebJul 25, 2014 · 1 mole Br2 = 159.808g Br2 = 6.022 x 1023 molecules Br2 4.89 x 1020 molecules Br2 x 1mol Br2/6.022 x 1023 molecules Br2 x 159.808g Br2/mol Br2 = 0.130g … WebQuestion: A 0.0651-mol sample of a nutrient substance, with a formula weight of 114 g/mol, is burned in a bomb calorimeter containing 8.35 x 102 g H2O. Given that the fuel value is 4.78 x 101 in nutritional Cal when the temperature of the water is increased by 4.26°C, calculate the fuel value in kJ. Enter your answer in scientific notation.
[Solved] please solve When 0.0651 mol of an unknown …
WebEnter the email address you signed up with and we'll email you a reset link. WebAll tutors are evaluated by Course Hero as an expert in their subject area. Answered by sabazaman24 The heat of combustion of hydrocarbon is - 41.04 KJ/mol Step-by-step explanation Data Given: mass of hydrocarbon= 0.0651 mole Raise in temperature= 2.19 Celsius Heat capacity= 1.229 KJ/C To find: heat of combustion=?? Solution: billy the kid sites
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WebApr 28, 2024 · The molarity of the solution formed is 0.0337 M From the question, We are to determine the molarity of the solution formed. First, we will determine the number of moles MgI₂ dissolved Mass of MgI₂ dissolved = 468 mg = 0.468 g From the formula Molar mass of MgI₂ = 278.1139 g/mol ∴ Number of moles of MgI₂ present = WebWhen 0.0651 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. If the heat capacity of the bomb calorimeter is 1.229 kJ/°C, what is the heat of combustion for the unknown hydrocarbon? This problem has been solved! WebMar 7, 2016 · Explanation: So the smallest molar quantity is that of oxgen, C = 0.0130 ⋅ mol 0.0065 ⋅ mol; H = 0.0390 ⋅ mol 0.0065 ⋅ mol; O = 0.0065 ⋅ mol 0.0065 ⋅ mol. So CnH mOp = C2H 6O. So that's the empirical formula, the simplest whole number ratio that defines constituent atoms in a species. cynthia fronterhouse